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The problem asks to find the equation of the line in **standard form** that passes through the points \((-3, -11)\) and \((-3, -10)\).

### Step-by-Step Solution:

1. **Identify the type of line:**
   Both points have the same x-coordinate \(-3\), so this is a **vertical line**.

2. **Equation of a vertical line:**
   For a vertical line, the equation is of the form:
   \[
   x = c
   \]
   where \(c\) is the constant x-coordinate. Since both points share the x-coordinate \(-3\), the equation of the line is:
   \[
   x = -3
   \]

3. **Standard form:**
   The standard form of a line equation is \(Ax + By = C\). For a vertical line, we can rewrite the equation \(x = -3\) as:
   \[
   x + 0y = -3
   \]
   This is the standard form, where \(A = 1\), \(B = 0\), and \(C = -3\).

### Final Answer:
The equation of the line in standard form is:
\[
x + 0y = -3
\]

Would you like any additional details or have any questions?

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Here are some related questions to practice:

1. How do you find the slope of a vertical line?
2. What is the general form of a horizontal line equation?
3. How do you find the equation of a line through two points with different x- and y-coordinates?
4. What does the slope-intercept form look like for vertical and horizontal lines?
5. How does the standard form of a line differ from the slope-intercept form?

**Tip:** For vertical lines, the slope is undefined because the change in x is zero, leading to a division by zero when calculating the slope.

Find the equation of the line in standard form that passes through the points (-3, -11) and (-3, -10).

Find the equation of the vertical line passing through the points (-3, -11) and (-3, -10). The solution involves identifying the line type and expressing the equation in standard form.

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