To solve for \( x \) in the equation \( 2.4045x + 1.323y = 27 \), we isolate \( x \).

### Steps:

1. Subtract \( 1.323y \) from both sides:
   \[
   2.4045x = 27 - 1.323y
   \]

2. Divide both sides by \( 2.4045 \) to isolate \( x \):
   \[
   x = \frac{27 - 1.323y}{2.4045}
   \]

Thus, the expression for \( x \) is:
\[
x = \frac{27 - 1.323y}{2.4045}
\]

Would you like to substitute any value for \( y \) or need further details on solving?

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Here are 5 related questions to expand on this:

1. What happens to \( x \) if \( y = 0 \)?
2. How would you solve for \( y \) instead of \( x \) in this equation?
3. Can you graph the equation \( 2.4045x + 1.323y = 27 \)?
4. What is the value of \( x \) if \( y = 5 \)?
5. How does changing the coefficient of \( y \) affect the equation?

**Tip:** When isolating a variable, always remember to perform the same operations on both sides of the equation.

Learn how to solve for x in the linear equation 2.4045x + 1.323y = 27 with a clear step-by-step solution. This problem involves key algebraic concepts, such as solving for a variable in linear equations, and is suitable for students in Grades 8-10.

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