if t is 0 and 5 and p is 4900 and 5550 what is the rate of change?

The rate of change can be calculated using the formula for the slope (or rate of change) between two points \((t_1, p_1)\) and \((t_2, p_2)\) on a line:

\[
\text{Rate of change} = \frac{p_2 - p_1}{t_2 - t_1}
\]

Here, the given values are:
- \(t_1 = 0\), \(p_1 = 4900\)
- \(t_2 = 5\), \(p_2 = 5550\)

Substituting these into the formula:

\[
\text{Rate of change} = \frac{5550 - 4900}{5 - 0} = \frac{650}{5} = 130
\]

So, the rate of change is **130 units per time unit**.

Would you like further details on how this is applied or its significance? Here are some related questions:

1. What does a positive rate of change indicate in a real-world context?
2. How would the rate of change be interpreted if the values were decreasing?
3. Can you apply this method to non-linear changes, or does it only work for straight lines?
4. What are some other ways to measure change in non-linear functions?
5. How does this concept relate to velocity in physics?

**Tip:** Rate of change gives you an idea of how one quantity changes in relation to another over time or space, helping to understand trends or patterns.

If t is 0 and 5 and p is 4900 and 5550, what is the rate of change?

Learn how to calculate the rate of change between two points with time values t = 0, 5 and position values p = 4900, 5550. This problem demonstrates the use of the rate of change formula (p2 - p1) / (t2 - t1), ideal for students in Grades 6-8.

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