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The problem states:

**If the initial size of a tumor is doubled every year, what is the size of the tumor in 5 years if it starts with a size of 4 cm³?**

To solve this problem, we use the formula for exponential growth:

\[
\text{Final size} = \text{Initial size} \times (2)^{\text{number of years}}
\]

Given:
- Initial size = 4 cm³
- Growth factor per year = 2 (since the size doubles)
- Number of years = 5

Substituting these values into the formula:

\[
\text{Final size} = 4 \times (2)^5 = 4 \times 32 = 128 \, \text{cm}^3
\]

Therefore, the correct answer is:

**D. 128 cm³**

Would you like further details on this solution or have any questions?

### Related Questions:
1. How would the formula change if the tumor tripled in size every year?
2. What would be the size of the tumor after 10 years under the same conditions?
3. How can exponential growth be modeled in other contexts, like population growth?
4. How would the tumor size change if it only grew by 50% each year?
5. What is the general formula for exponential growth or decay?

### Tip:
Always check if the problem involves exponential growth or decay by identifying if quantities are repeatedly multiplied by a constant factor over time.

If the initial size of a tumor is doubled every year, what is the size of the tumor in 5 years if it starts with a size of 4 cm³?

Learn how to calculate the size of a tumor after 5 years if it doubles in size each year starting from 4 cm³. This problem illustrates exponential growth, a fundamental concept in algebra, suitable for students in Grades 6-8.

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