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The given equation is:

\[
7(x + 4) = 35
\]

To solve for \(x\), follow these steps:

1. **Distribute the 7** to the terms inside the parentheses:

   \[
   7x + 28 = 35
   \]

2. **Isolate the term with \(x\)** by subtracting 28 from both sides:

   \[
   7x = 35 - 28
   \]

   \[
   7x = 7
   \]

3. **Solve for \(x\)** by dividing both sides by 7:

   \[
   x = \frac{7}{7}
   \]

   \[
   x = 1
   \]

So, the value of \(x\) is **1**.

Would you like more details or have any questions?

Here are 5 related questions to practice:

1. Solve \(6(x - 3) = 18\).
2. If \(5(x + 2) = 25\), what is \(x\)?
3. Solve \(3(2x + 5) = 24\).
4. What is \(x\) in the equation \(4(x + 1) = 20\)?
5. If \(8(x - 4) = 32\), solve for \(x\).

**Tip:** Always check your solution by substituting the value of \(x\) back into the original equation!

Learn how to solve the linear equation 7(x + 4) = 35 with a clear, step-by-step solution. This problem demonstrates key algebraic concepts such as the distributive property and solving for variables. Suitable for students in Grades 6-8.

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