so would this be -2i,-4j:So, the vector is BA→=⟨−2,−4⟩*BA*=⟨−2,−4⟩

Yes, you are correct! Given that the vector \( \overrightarrow{BA} \) has the components \( \langle -2, -4 \rangle \), you can express it as:

\[
\overrightarrow{BA} = -2\mathbf{i} - 4\mathbf{j}
\]

Here:
- \( -2\mathbf{i} \) corresponds to the \( x \)-component.
- \( -4\mathbf{j} \) corresponds to the \( y \)-component.

This represents a vector in two-dimensional space, where \( \mathbf{i} \) and \( \mathbf{j} \) are the unit vectors in the \( x \)- and \( y \)-directions, respectively.

Would you like more details or have any questions? Here are some related questions to explore further:

1. How do you calculate the magnitude of the vector \( \overrightarrow{BA} \)?
2. What are unit vectors, and how are they used in vector notation?
3. How do you find the direction angle of the vector \( \overrightarrow{BA} \)?
4. What is the geometric interpretation of the vector \( \overrightarrow{BA} \)?
5. How do you add and subtract vectors in component form?

**Tip:** To find the magnitude of a vector, use the formula \( |\mathbf{v}| = \sqrt{x^2 + y^2} \).

Explore how to represent vector BA as (-2i, -4j) in component form. Learn about vectors in two-dimensional space, including their components and unit vectors. Suitable for high school students studying vector algebra.

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