Math Problem Statement
Solve a and b when a=3i-4j+2k and b = -i + 2j-3k
Solution
Given the vectors and , we can perform a variety of vector operations.
1. Magnitude of and
The magnitude (or length) of a vector is given by:
For :
For :
2. Dot Product
The dot product of two vectors and is calculated as:
3. Cross Product
The cross product is a vector given by:
\mathbf{i} & \mathbf{j} & \mathbf{k} \\ 3 & -4 & 2 \\ -1 & 2 & -3 \end{vmatrix}$$ This determinant expands as: $$\mathbf{a} \times \mathbf{b} = \mathbf{i}\left((-4)(-3) - (2)(2)\right) - \mathbf{j}\left((3)(-3) - (2)(-1)\right) + \mathbf{k}\left((3)(2) - (-4)(-1)\right)$$ Simplifying: $$\mathbf{a} \times \mathbf{b} = \mathbf{i}(12 - 4) - \mathbf{j}(-9 + 2) + \mathbf{k}(6 - 4)$$ $$\mathbf{a} \times \mathbf{b} = 8\mathbf{i} + 7\mathbf{j} + 2\mathbf{k}$$ ### 4. Angle Between $$\mathbf{a}$$ and $$\mathbf{b}$$ The angle $$\theta$$ between two vectors is given by: $$\cos \theta = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{a}| |\mathbf{b}|}$$ Substituting the values: $$\cos \theta = \frac{-17}{\sqrt{29} \cdot \sqrt{14}}$$ $$\cos \theta = \frac{-17}{\sqrt{406}} \approx -0.844$$ Thus, the angle $$\theta$$ is: $$\theta \approx \cos^{-1}(-0.844) \approx 147.6^\circ$$ Would you like more details on any specific part or further calculations? --- **Here are some related questions:** 1. How do you interpret the cross product of two vectors geometrically? 2. What are the properties of the dot product and cross product of vectors? 3. How do you find the projection of one vector onto another? 4. Can you find a unit vector in the direction of $$\mathbf{a} \times \mathbf{b}$$? 5. What is the physical significance of the angle between two vectors? **Tip:** The cross product of two vectors results in a vector that is perpendicular to the plane containing the original vectors.Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Vector Algebra
Dot Product
Cross Product
Vector Magnitude
Angle Between Vectors
Formulas
Magnitude of vector |v| = sqrt(x^2 + y^2 + z^2)
Dot product a · b = ax * bx + ay * by + az * bz
Cross product a × b = determinant of the matrix with unit vectors i, j, k and the components of a and b
Angle θ between vectors: cos θ = (a · b) / (|a| |b|)
Theorems
Pythagorean Theorem for vector magnitude
Dot Product and Cross Product Theorems
Suitable Grade Level
Grades 11-12
Related Recommendation
Vector Dot Product, Cross Product, and Angle Between Vectors a = 2i + 4j - 3k and b = i + 3j + 2k
Vector Addition, Subtraction, and Unit Vector Calculations
Cross Product of Vectors a=3i-4j+2k and b=-i+2j-3k
Find a Vector of Magnitude 14 Orthogonal to Given Vectors and Angle Between Them
Dot Product of Vectors A = 3i + 2j + 4k and B = 2i - 4j + 5k