https://file.aiquickdraw.com/mathbot/file/17270742914574mjdqqya.jpg

The problem in the image asks to calculate the length of segment \( YX \) given that the segments \( AB \), \( EF \), \( YX \), and \( KM \) are pairwise proportional. The provided values are:

- \( AB = 1 \, \text{dm} \),
- \( EF = 8 \, \text{dm} \),
- \( KM = 88 \, \text{dm} \).

To solve for \( YX \), we can set up a proportion between the segments because they are said to be proportional:

\[
\frac{AB}{EF} = \frac{YX}{KM}
\]

Substitute the known values into this proportion:

\[
\frac{1}{8} = \frac{YX}{88}
\]

Now, solve for \( YX \) by cross-multiplying:

\[
YX = \frac{1 \times 88}{8} = 11 \, \text{dm}.
\]

Thus, the length of segment \( YX \) is \( 11 \, \text{dm} \).

Would you like more details or have any other questions?

### Related Questions:
1. How can we derive proportionality relations in similar triangles?
2. What are the properties of proportional line segments?
3. How can we verify if segments are proportional in a geometric figure?
4. What are other real-life applications of proportionality in geometry?
5. How do proportionality and similarity relate in triangles?

**Tip**: Always double-check units when solving geometry problems to ensure they are consistent!

It is known that segments AB, EF, and YX, KM are pairwise proportional segments. AB = 1 dm, EF = 8 dm, and KM = 88 dm. Calculate the length of segment YX!

Learn how to calculate the length of segment YX using proportional segments. Given AB = 1 dm, EF = 8 dm, and KM = 88 dm, solve for YX using a simple proportion formula. Suitable for students in Grades 6-8.

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