Math Problem Statement

Given segment DF with point E between DF.  Find DF if DE=8 and EF=14.

Solution

Given that point EE lies between points DD and FF on segment DFDF, we can find the length of DFDF by adding the lengths of DEDE and EFEF.

The relationship is:

DF=DE+EFDF = DE + EF

We are given:

  • DE=8DE = 8
  • EF=14EF = 14

Now, substitute these values into the equation:

DF=8+14=22DF = 8 + 14 = 22

So, the length of DFDF is 2222 units.

Would you like more details on this? Here are 5 related questions that might interest you:

  1. What is the length of DFDF if DE=5DE = 5 and EF=9EF = 9?
  2. If EE is the midpoint of DFDF, what are the lengths of DEDE and EFEF when DF=30DF = 30?
  3. If DE=xDE = x and EF=x+6EF = x + 6, what is the length of DFDF in terms of xx?
  4. What is the length of EFEF if DF=20DF = 20 and DE=7DE = 7?
  5. How does changing the position of EE affect the lengths of DEDE and EFEF?

Tip: For any three points on a line where one point is between the other two, the length of the entire segment is the sum of the lengths of the two smaller segments.

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Math Problem Analysis

Mathematical Concepts

Geometry
Segments

Formulas

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Theorems

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Suitable Grade Level

Grades 6-8