Given segment DF with point E between DF.  Find DF if DE=8 and EF=14.


Given that point \( E \) lies between points \( D \) and \( F \) on segment \( DF \), we can find the length of \( DF \) by adding the lengths of \( DE \) and \( EF \).

The relationship is:

\[
DF = DE + EF
\]

We are given:
- \( DE = 8 \)
- \( EF = 14 \)

Now, substitute these values into the equation:

\[
DF = 8 + 14 = 22
\]

So, the length of \( DF \) is \( 22 \) units.

Would you like more details on this? Here are 5 related questions that might interest you:

1. What is the length of \( DF \) if \( DE = 5 \) and \( EF = 9 \)?
2. If \( E \) is the midpoint of \( DF \), what are the lengths of \( DE \) and \( EF \) when \( DF = 30 \)?
3. If \( DE = x \) and \( EF = x + 6 \), what is the length of \( DF \) in terms of \( x \)?
4. What is the length of \( EF \) if \( DF = 20 \) and \( DE = 7 \)?
5. How does changing the position of \( E \) affect the lengths of \( DE \) and \( EF \)?

**Tip:** For any three points on a line where one point is between the other two, the length of the entire segment is the sum of the lengths of the two smaller segments.

Learn how to find the length of segment DF when point E lies between points D and F, given DE = 8 and EF = 14. This problem involves basic geometry concepts related to segments and their lengths. Suitable for students in Grades 6-8.

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