https://file.aiquickdraw.com/mathbot/file/1726406636470a8hovr2i.jpg

In the image, you are solving for \( f(2) \) given the function \( f(x) = 2(x) + \sqrt{y} - 2 \).

From what I can deduce, it looks like you may have assumed \( y \) as a constant, possibly 4, to get \( \sqrt{4} = 2 \), which you then used to compute \( f(2) = 6 \). Here's the breakdown:

1. You substituted \( x \) with 2 in the function:
   \[
   f(2) = 2(2) + \sqrt{4} - 2
   \]
2. You simplified \( 2(2) \) to 4.
3. You found \( \sqrt{4} \) to be 2.
4. Then, you calculated \( 4 + 2 - 2 = 4 \).

However, the final calculation \( 4 + 2 - 2 \) should actually be 4, not 6 as you've written.

If \( y \) is indeed a constant value of 4, then \( f(2) = 4 \), not 6.

Would you like more details on how to solve such equations or do you have any other questions?

Here are some related questions:
1. What happens to the function if \( y \) changes?
2. How would you graph this function for different values of \( y \)?
3. What is the impact of changing the value of \( x \) on \( f(x) \)?
4. Can \( y \) be a function of \( x \) in this context? How would that affect the equation?
5. How can you determine the domain and range of this function?

**Tip:** Always recheck your arithmetic calculations to ensure they sum up correctly, especially in functions involving multiple terms.

Learn how to solve the function f(x) = 2x + √y - 2 step-by-step. This problem involves function evaluation, substitution, and square roots, suitable for students in Grades 8-10.

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