shopkeeper sells 1 kg of product A costing Rs. 30/kg to Each Bunty and Babli at Rs. 33/ kg. He sold 'x' gm to Bunty instead of 1 kg and sold 950 gm to Babli instead of 1 kg by using defective weights. If he makes a total profit of Rs. 9.3 by selling, then wat is the value of x?

To solve this problem, we need to find the value of \(x\) grams (the amount actually sold to Bunty) when the shopkeeper's total profit is Rs. 9.3.

### Step-by-Step Solution:

1. **Determine the selling price and cost price:**

   The shopkeeper sells 1 kg of product A at Rs. 33 per kg to both Bunty and Babli. However, the shopkeeper uses defective weights:
   - He sells \(x\) grams to Bunty instead of 1 kg.
   - He sells 950 grams to Babli instead of 1 kg.

   The cost price for 1 kg of product A is Rs. 30.

2. **Calculate the actual quantity sold:**

   - Quantity sold to Bunty: \(x\) grams.
   - Quantity sold to Babli: 950 grams.

   The total quantity sold in kilograms is:

   \[
   \text{Total quantity sold} = \frac{x}{1000} + \frac{950}{1000} \text{ kg}
   \]

   \[
   \text{Total quantity sold} = \frac{x + 950}{1000} \text{ kg}
   \]

3. **Calculate the total cost price:**

   The cost price per kg is Rs. 30. So, the total cost price for the quantity sold is:

   \[
   \text{Total cost price} = 30 \times \frac{x + 950}{1000}
   \]

4. **Calculate the total selling price:**

   - Selling price to Bunty: Rs. 33 (for 1 kg, but he actually sold \(x\) grams)
   - Selling price to Babli: Rs. 33 (for 1 kg, but he actually sold 950 grams)

   The total selling price is:

   \[
   \text{Total selling price} = 33 + 33 = 66 \text{ Rs.}
   \]

5. **Calculate the profit:**

   The profit is the difference between the total selling price and the total cost price:

   \[
   \text{Total profit} = \text{Total selling price} - \text{Total cost price}
   \]

   Given that the total profit is Rs. 9.3, we set up the equation:

   \[
   9.3 = 66 - 30 \times \frac{x + 950}{1000}
   \]

6. **Solve for \(x\):**

   Rearranging the equation, we get:

   \[
   9.3 = 66 - \frac{30(x + 950)}{1000}
   \]

   Simplify the equation:

   \[
   9.3 = 66 - \frac{30x + 28500}{1000}
   \]

   Multiply both sides by 1000:

   \[
   9300 = 66000 - (30x + 28500)
   \]

   Simplify further:

   \[
   9300 = 66000 - 28500 - 30x
   \]

   \[
   9300 = 37500 - 30x
   \]

   Rearrange to find \(x\):

   \[
   30x = 37500 - 9300
   \]

   \[
   30x = 28200
   \]

   \[
   x = \frac{28200}{30}
   \]

   \[
   x = 940
   \]

### Conclusion:

The value of \(x\) is **940 grams**.

Would you like to know more details, or have any questions? Here are 5 related questions that might interest you:

1. How would the profit change if the cost price per kg was different?
2. What would happen if the weights used were more defective, say selling only 900 grams to Babli?
3. How can we calculate the total revenue in this scenario?
4. How do we interpret the profit margin percentage from the total sales?
5. What would be the value of \(x\) if the total profit was set to Rs. 8 instead of Rs. 9.3?

**Tip:** Always check the weights used by shopkeepers to ensure you receive the correct quantity!

A shopkeeper sells 1 kg of product A costing Rs. 30/kg to each Bunty and Babli at Rs. 33/kg. He sold 'x' gm to Bunty instead of 1 kg and sold 950 gm to Babli instead of 1 kg by using defective weights. If he makes a total profit of Rs. 9.3 by selling, then what is the value of x?

Solve a real-world algebra problem where a shopkeeper uses defective weights while selling products. Calculate the value of x grams sold to Bunty when the total profit is Rs. 9.3. This problem involves linear equations and basic profit calculations, suitable for Grades 8-10.

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