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The question asks how many ways Josephine can choose one book from each category:

- 7 chemistry books,
- 3 history books,
- 6 statistics books.

Since she needs to choose one book from each type, the total number of ways to choose one book from each category is the product of the number of choices from each category.

Thus, the total number of ways to choose the books is:

\[
7 \times 3 \times 6 = 126
\]

So, the total number of ways Josephine can choose the three books is **126**.

Would you like more details, or have any questions about this problem?

Here are 5 related questions you might find helpful:
1. How many ways can Josephine choose 2 chemistry books and 1 history book?
2. If Josephine decides to pick only 2 books (one history and one statistics), how many ways can she do that?
3. What if there were 5 history books instead of 3—how many combinations would be possible then?
4. How would the total change if Josephine had to choose 2 books from chemistry and 1 from statistics, ignoring history?
5. How many total combinations would be possible if Josephine could choose any 3 books regardless of type?

**Tip**: Problems like this can be solved using the multiplication principle of counting, which is a fundamental concept in combinatorics.

Josephine has seven chemistry books, three history books, and six statistics books. She wants to choose one book of each type to study. In how many ways can she choose the three books?

Find out how many ways Josephine can choose one chemistry, one history, and one statistics book from a selection of 7, 3, and 6 books, respectively. Learn about the multiplication principle of counting and its application in combinatorics. Suitable for middle school students.

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