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The question asks us to find the class interval with the highest frequency. Let's analyze the problem step-by-step:

1. **Frequency Distribution Table**:
   - The table shows the distribution of sales commissions received by salesmen.
   - Each interval represents a range of commissions (in thousands) and their respective frequencies.

2. **Given Data**:
   - The class intervals and their frequencies are:
     - 150–158 : m
     - 159–167 : 16
     - 168–176 : 20
     - 177–185 : 21
     - 186–194 : 20
     - 195–203 : 15
     - 204–212 : 3

3. **Mean Commission**:
   - The average commission is given as 180.28 (in thousands).

4. **Calculating the Mode Class**:
   - The mode is usually in the class interval with the highest frequency. Here, the class interval 177–185 has the highest frequency, which is 21.

5. **Finding the Exact Answer**:
   - The highest frequency (21) corresponds to the class interval 177–185.
   - The midpoint of this class is \((177 + 185) / 2 = 181\).

So, the correct answer is **D) 181**.

Would you like further details on this, or have any other questions? Here are some related questions:

1. How is the mode calculated from a frequency distribution table?
2. What is the difference between mean, median, and mode?
3. How do we determine the class interval for which a certain property is maximum?
4. How do you calculate the mean from a frequency distribution?
5. What are other ways to represent data distributions besides frequency tables?

**Tip**: When dealing with frequency distributions, always identify the highest frequency first to quickly determine the mode.

Jika rata-rata komisi yang diperoleh salesman adalah 180,28 (dalam puluhan ribu), maka jumlah komisi terbanyak yang diterima oleh salesman adalah berapa (dalam puluhan ribu)?

Learn how to calculate the mode of a frequency distribution table when given the mean commission of 180.28. This problem involves analyzing class intervals and determining the class with the highest frequency to find the mode. Perfect for high school students tackling frequency distribution problems in statistics.

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