Suppose that 11 coins are tossed. Let A be the event that you get at most 10 heads. Then find the number of heads that is the complement of A.

The problem states that 11 coins are tossed, and event \( A \) is the event of getting at most 10 heads. We are tasked with finding the number of heads that corresponds to the complement of \( A \).

### Understanding the complement of event \( A \):

- Event \( A \): Getting at most 10 heads means that the number of heads can range from 0 to 10.
- Complement of \( A \): The complement of this event would be the event where **more than 10 heads** are obtained.

However, since only 11 coins are tossed, the only way to get more than 10 heads is to get **exactly 11 heads**.

Thus, the complement of \( A \) is the event of getting exactly 11 heads.

### Conclusion:
The number of heads that corresponds to the complement of event \( A \) is **11 heads**.

Would you like more details or have any other questions?

Here are some related questions you might consider:

1. What is the probability of getting exactly 11 heads when tossing 11 coins?
2. How do you calculate the probability of getting at most 10 heads when tossing 11 coins?
3. What is the probability of getting at least 1 head when tossing 11 coins?
4. What is the expected number of heads when tossing 11 coins?
5. How does the binomial distribution apply to this problem?

**Tip:** The complement rule in probability is a useful technique, stating that the probability of the complement of an event is 1 minus the probability of the event itself.

This problem explores the complement of an event in probability by considering the case of tossing 11 coins. It covers key concepts like the complement rule, where the goal is to find the number of heads that corresponds to the complement of getting at most 10 heads. Suitable for students in Grades 9-12.

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