Thank you for the correction. Let's redo the calculation with the correct base and height values.

We have:
- Base \( BC = 12 \, \text{cm} \)
- Height relative to base \( AB = 9 \, \text{cm} \)
- Angle \(\angle A = 130^\circ\)

We need to use the sine of the angle to find the height corresponding to base \( BC \).

Using the formula for the area of a parallelogram:
\[ \text{Area} = \text{base} \times \text{height} \times \sin(\theta) \]

So, with base \( BC \):
\[ \text{Height} = AB \times \sin(130^\circ) \]
\[ \text{Height} = 9 \, \text{cm} \times \sin(130^\circ) \]
\[ \sin(130^\circ) = \sin(180^\circ - 50^\circ) = \sin(50^\circ) \approx 0.766 \]

Thus,
\[ \text{Height} = 9 \, \text{cm} \times 0.766 \approx 6.894 \, \text{cm} \]

Now we can find the area with the base \( BC = 12 \, \text{cm} \):
\[ \text{Area} = 12 \, \text{cm} \times 6.894 \, \text{cm} \approx 82.728 \, \text{cm}^2 \]

Correct to 3 significant figures, the area is:
\[ \text{Area} \approx 82.7 \, \text{cm}^2 \]

Therefore, the answer is \( \boxed{82.7 \, \text{cm}^2} \).

Would you like further details or have any other questions?

Here are 5 questions you might want to ask next:
1. How do you derive the formula for the area of a parallelogram?
2. Can you explain how to find the height in different geometrical shapes?
3. What is the sine function and how is it used in trigonometry?
4. How do you round numbers to significant figures?
5. What are some common mistakes to avoid when solving area problems in geometry?

**Tip:** When calculating areas, double-check which side is the base and which is the height to ensure accurate results.

Learn how to calculate the area of a parallelogram using trigonometry. This problem involves finding the area of a parallelogram with given base BC = 12 cm and height AB = 9 cm. Detailed step-by-step solution provided.

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