Math Problem Statement

Solution

To find the inverse function f1(x)f^{-1}(x) for the given function f(x)=(x77)15+9f(x) = \left( \frac{x - 7}{7} \right)^{\frac{1}{5}} + 9, we will follow these steps:

  1. Rewrite the function as an equation: y=(x77)15+9y = \left( \frac{x - 7}{7} \right)^{\frac{1}{5}} + 9

  2. Swap xx and yy to find the inverse: x=(y77)15+9x = \left( \frac{y - 7}{7} \right)^{\frac{1}{5}} + 9

  3. Isolate yy: x9=(y77)15x - 9 = \left( \frac{y - 7}{7} \right)^{\frac{1}{5}}

  4. Raise both sides to the power of 5 to eliminate the fractional exponent: (x9)5=y77(x - 9)^5 = \frac{y - 7}{7}

  5. Multiply both sides by 7: 7(x9)5=y77(x - 9)^5 = y - 7

  6. Add 7 to both sides to solve for yy: y=7(x9)5+7y = 7(x - 9)^5 + 7

So, the inverse function is: f1(x)=7(x9)5+7f^{-1}(x) = 7(x - 9)^5 + 7

Do you want details or have any questions? Here are five more questions you can ask:

  1. How do you find the inverse of a function in general?
  2. Can you show how to find the derivative of the inverse function?
  3. What are the properties of inverse functions?
  4. How can you verify that two functions are inverses of each other?
  5. Can you explain the domain and range of the inverse function?

Tip: When finding the inverse of a function, always remember to swap xx and yy and then solve for yy.

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Math Problem Analysis

Mathematical Concepts

Functions
Inverse Functions
Exponentiation
Equations

Formulas

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Theorems

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Suitable Grade Level

Grades 11-12