what is the area of a right trialangle with 9cm and 6cm

To find the area of a right triangle, you can use the formula:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

Given:
- Base = 9 cm
- Height = 6 cm

Substituting these values into the formula:

\[
\text{Area} = \frac{1}{2} \times 9 \, \text{cm} \times 6 \, \text{cm} = \frac{1}{2} \times 54 \, \text{cm}^2 = 27 \, \text{cm}^2
\]

So, the area of the right triangle is **27 cm²**.

Would you like more details or have any questions?

Here are 8 related questions:
1. What is the hypotenuse of the triangle?
2. How would the area change if the base was doubled?
3. What is the perimeter of this triangle?
4. How do you find the area of any triangle given the base and height?
5. Can you find the area if the triangle's base was 10 cm and the height was 8 cm?
6. How would the area change if the height was reduced to 3 cm?
7. What would be the area if the base and height were both 12 cm?
8. How do you calculate the area of a triangle if only the sides are given?

**Tip:** The area of a right triangle can be easily calculated using the base and height, which are the two sides perpendicular to each other.

Discover how to calculate the area of a right triangle with a base of 9cm and a height of 6cm. Follow a detailed step-by-step solution using the area formula (1/2) * base * height. Learn about the Pythagorean theorem and its application in calculating triangle areas. Suitable for students in Grades 7-9.

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