https://file.aiquickdraw.com/mathbot/file/17260986715475055rb4q.jpg

To determine the magnitude and bearing of the vector, we can follow these steps:

### 1. **Magnitude of the Vector:**
The vector is shown as being 2 inches long on the diagram, and the scale is given as \( 1 \text{ inch} = 50 \text{ mph} \). Therefore, the magnitude of the vector is:

\[
\text{Magnitude} = 2 \, \text{inches} \times 50 \, \text{mph/inch} = 100 \, \text{mph}.
\]

### 2. **Bearing of the Vector:**
The vector is shown at an angle of \( 60^\circ \) counterclockwise from the negative x-axis (west direction). To convert this into a standard bearing (measured clockwise from the positive y-axis or north), we subtract this angle from \( 360^\circ \):

\[
\text{Bearing} = 360^\circ - 60^\circ = 300^\circ.
\]

### Conclusion:
- The magnitude of the vector is approximately **100 mph**.
- The bearing is **300°**.

However, none of the answer choices exactly match this. The closest answer is "112 mph 300°," which could be a rounding or typographical error.

Let me know if you'd like further clarification, or if you have any additional questions!

Here are five related questions to explore:
1. What is the difference between bearing and direction in vector analysis?
2. How does vector magnitude relate to real-world velocity measurements?
3. How can vectors be decomposed into components along the x and y axes?
4. What are the rules for adding vectors geometrically?
5. How does changing the angle affect the components of a vector?

**Tip:** Always pay close attention to the units of measure and scales in vector diagrams—they can drastically change the interpretation of the results.

What is the approximate magnitude and bearing of the vector shown in the diagram?

Learn how to calculate the magnitude and bearing of a vector shown in a diagram with a scale of 1 inch = 50 mph. The vector is 2 inches long and has an angle of 60°. The result gives a magnitude of 100 mph and a bearing of 300°.

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