Compute the X component the vector: 6 m/s at 240 deg

To compute the X-component of a vector given its magnitude and direction, we can use the formula:

\[
X = \text{{magnitude}} \times \cos(\theta)
\]

Where:
- The magnitude is \(6 \, \text{m/s}\).
- \(\theta\) is the angle, which is \(240^\circ\).

Let's calculate the X-component of the vector.The X-component of the vector with a magnitude of \(6 \, \text{m/s}\) at an angle of \(240^\circ\) is approximately \(-3 \, \text{m/s}\).

Would you like further details on this calculation or have any questions?

Here are 5 related questions to consider:
1. How do you calculate the Y-component of the same vector?
2. What is the significance of negative components in vector calculations?
3. How does changing the angle to 120 degrees affect the X-component?
4. Can you find the resultant vector when adding this vector to another?
5. How would the X-component change if the magnitude were doubled?

**Tip:** Always check whether angles are measured in degrees or radians when applying trigonometric functions.

Learn how to compute the X-component of a vector with a magnitude of 6 m/s at an angle of 240 degrees using trigonometric functions. Understand the formula X = magnitude × cos(θ) and its application in vector mathematics.

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