The equation you provided is:

\[
6.31 = d^2 + 4
\]

To solve for \( d \), follow these steps:

### Step 1: Subtract 4 from both sides.
\[
6.31 - 4 = d^2
\]
\[
2.31 = d^2
\]

### Step 2: Take the square root of both sides.
\[
d = \sqrt{2.31}
\]

### Step 3: Calculate the square root.
\[
d \approx 1.52
\]

So, \( d \approx 1.52 \).

Would you like more details on this solution?

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Here are 5 related questions:
1. What is the square root of 16.31 in a similar equation?
2. How would the equation change if the constant was 5 instead of 4?
3. What are the properties of quadratic equations like this one?
4. How would the result differ if the equation was \( 6.31 = d^3 + 4 \)?
5. How can you graph this type of equation?

**Tip:** Always double-check your solution by plugging the value of \( d \) back into the original equation to verify its correctness.

Discover how to solve the equation d^2 + 4 = 6.31 with a step-by-step solution. This problem highlights key algebraic concepts like quadratic equations and square roots, perfect for students in Grades 7-9.

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