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The equation given is:

\[ 2x^2 + 3x + y = 5 \]

You are asked to find \( y \) when \( x = 2 \).

First, substitute \( x = 2 \) into the equation:

\[ 2(2)^2 + 3(2) + y = 5 \]

Calculate \( 2(2)^2 \):

\[ 2(2)^2 = 2 \cdot 4 = 8 \]

Calculate \( 3(2) \):

\[ 3(2) = 6 \]

Now substitute these values back into the equation:

\[ 8 + 6 + y = 5 \]

Combine the constants:

\[ 14 + y = 5 \]

To find \( y \), isolate it on one side of the equation:

\[ y = 5 - 14 \]
\[ y = -9 \]

Therefore, when \( x = 2 \), \( y = -9 \).

If you have any questions or need further details, feel free to ask.

Here are 5 questions you might want to ask:
1. How do you isolate a variable in an equation?
2. Can you explain how to solve equations with multiple variables?
3. What are the steps to substitute values into an equation?
4. How do you solve quadratic equations for specific values?
5. Can you provide examples of solving equations with substitutions?

**Tip:** When solving equations, carefully follow the order of operations and double-check each step to ensure accuracy.

Learn how to solve the equation 2x^2 + 3x + y = 5 for y when x = 2. This problem involves substituting values, isolating variables, and applying algebraic operations step-by-step. Suitable for high school students.

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