Math Problem Statement

حل المسألة

Solution

The image contains an equation written in Arabic. The equation is:

x2+4x+5=0x^2 + 4x + 5 = 0

To solve the quadratic equation x2+4x+5=0x^2 + 4x + 5 = 0, we can use the quadratic formula:

x=b±b24ac2ax = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}

For the given equation, a=1a = 1, b=4b = 4, and c=5c = 5.

  1. Calculate the discriminant: Δ=b24ac=42415=1620=4\Delta = b^2 - 4ac = 4^2 - 4 \cdot 1 \cdot 5 = 16 - 20 = -4

Since the discriminant (Δ\Delta) is negative, the equation has complex roots.

  1. Find the roots using the quadratic formula: x=4±421=4±2i2=2±ix = \frac{{-4 \pm \sqrt{-4}}}{2 \cdot 1} = \frac{{-4 \pm 2i}}{2} = -2 \pm i

Therefore, the solutions to the equation x2+4x+5=0x^2 + 4x + 5 = 0 are:

x=2+ix = -2 + i x=2ix = -2 - i

If you have any questions or need further details, feel free to ask.

Here are 5 questions you might want to ask:

  1. How do you solve a quadratic equation with a negative discriminant?
  2. Can you explain the steps of the quadratic formula in more detail?
  3. What are complex numbers and how are they represented?
  4. How do you find the roots of a quadratic equation with real coefficients?
  5. Can you provide examples of quadratic equations with real roots?

Tip: When solving quadratic equations, always check the discriminant first to determine the nature of the roots.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Complex Numbers

Formulas

Quadratic formula

Theorems

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Suitable Grade Level

High School