https://file.aiquickdraw.com/mathbot/file/1727182177162nexg3bft.jpg

To solve this problem, let's first break down the information from the image.

### Bead Counts:
- Yellow beads: 42
- Green beads: 28
- White beads: 12
- Red beads: 18

Total number of beads:
\[
42 \, (\text{yellow}) + 28 \, (\text{green}) + 12 \, (\text{white}) + 18 \, (\text{red}) = 100 \, (\text{total beads})
\]

### 1. Probability of **not** drawing a yellow or green bead:
Yellow and green beads together:
\[
42 \, (\text{yellow}) + 28 \, (\text{green}) = 70
\]

The probability of **not** drawing a yellow or green bead means drawing either a white or red bead:
\[
\text{Number of white and red beads} = 12 \, (\text{white}) + 18 \, (\text{red}) = 30
\]

Thus, the probability is:
\[
\frac{30}{100} = 0.30 = 30\%
\]

### 2. Probability of drawing a red or green bead:
Red and green beads together:
\[
18 \, (\text{red}) + 28 \, (\text{green}) = 46
\]

The probability is:
\[
\frac{46}{100} = 0.46 = 46\%
\]

### Final answers:
- Probability of **not** drawing a yellow or green bead: **30%**
- Probability of drawing a red or green bead: **46%**

Would you like further clarification or details?

Here are 5 related questions to further your understanding:
1. What is the probability of drawing a yellow bead from the bowl?
2. How would the probabilities change if 10 additional red beads were added?
3. What is the probability of drawing a white bead?
4. If Kayla draws two beads consecutively without replacement, what is the probability that both are red?
5. How would you calculate the probability of drawing a bead that is not red?

**Tip:** When calculating probabilities, always make sure to count the total number of possible outcomes correctly and clearly distinguish between the different events!

Kayla has a bowl of beads that contains 42 yellow beads, 28 green beads, 12 white beads, and 18 red beads. She randomly draws a bead from the bowl. The probability of Kayla not drawing a yellow or green bead is ___ %. The probability of Kayla drawing a red or green bead is ___ %.

This problem involves calculating the probability of not drawing a yellow or green bead and the probability of drawing a red or green bead from a bowl. The bowl contains 42 yellow beads, 28 green beads, 12 white beads, and 18 red beads, for a total of 100 beads. Suitable for Grades 6-8 students learning basic probability.

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