It seems like you're working with Ohm's Law, which is typically written as:

\[ V = I \times R \]

Where:
- \( V \) is the voltage (in volts),
- \( I \) is the current (in amperes),
- \( R \) is the resistance (in ohms).

Given:
- \( V = 13.5 \, \text{V} \)
- \( R = 300 \, \Omega \)

You need to find the current \( I \). Rearrange Ohm's Law to solve for \( I \):

\[
I = \frac{V}{R}
\]

Substituting the values:

\[
I = \frac{13.5 \, \text{V}}{300 \, \Omega} = 0.045 \, \text{A}
\]

So, the current \( I \) is \( 0.045 \) amperes (or 45 milliamperes).

Would you like any further details or explanations?

Here are 5 questions that build on this:
1. How would the current change if the resistance were doubled?
2. What would be the power dissipated in the resistor?
3. How can you calculate the resistance if only voltage and current are known?
4. What happens to the current if the voltage is increased to 27 V?
5. How does Ohm's Law relate to power calculations?

**Tip:** Always ensure the units are consistent when applying Ohm's Law (e.g., volts, ohms, and amperes).

Learn how to calculate current using Ohm's Law with a voltage of 13.5 volts and resistance of 300 ohms. This problem explains the relationship between voltage, current, and resistance in electric circuits. Suitable for Grades 9-12.

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