Let's solve the expression step by step:

Given the formula:

\[
I = \frac{V}{R}
\]

Substitute the given values \( V = 60 \) volts and \( R = 12 \times 10^3 \) ohms:

\[
I = \frac{60}{12 \times 10^3}
\]

First, calculate the denominator:

\[
12 \times 10^3 = 12,000 \, \text{ohms}
\]

Now, divide the numerator by the denominator:

\[
I = \frac{60}{12,000}
\]

Simplify the division:

\[
I = 0.005 \, \text{amperes} \, (A)
\]

So, the current \( I \) is \( 0.005 \, A \), which can also be written as \( 5 \, \text{mA} \) (milliamperes).

Would you like more details on this calculation or have any questions?

Here are 5 related questions to consider:

1. What would the current be if the voltage were doubled?
2. How does the current change if the resistance is halved?
3. What is the power dissipated in the resistor given the current and resistance?
4. How would you express the resistance in kilohms (kΩ)?
5. How does Ohm's law relate to the relationship between voltage, current, and resistance?

**Tip:** Remember that \( 1 \, \text{A} \) equals \( 1,000 \, \text{mA} \), which is useful when working with small currents.

Learn how to calculate electric current using Ohm's Law with an example problem. Given voltage (V) of 60 volts and resistance (R) of 12,000 ohms, find the current (I). Step-by-step solution included.

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