Math Problem Statement
function SS=xexiaoyuyelmd2(xe,ye,x1,x2)
xi=0:1:10000;
l1=10000;n=20000;dd=4.5;a0=90;gtl0=683000;
u1=1;
di2=zeros(ceil(x2)-ceil(x1)+1,1);
Pi2=zeros(ceil(x2)-ceil(x1)+1,1);
be2=zeros(ceil(x2)-ceil(x1)+1,1);
Ri2=zeros(ceil(x2)-ceil(x1)+1,1);
S3_i2=zeros(ceil(x2)-ceil(x1)+1,1);
S4_i2=zeros(ceil(x2)-ceil(x1)+1,1);
ph1i2=zeros(ceil(x2)-ceil(x1)+1,1);
SS3=zeros(ceil(x2)-ceil(x1)+1,1);
for u=ceil(x1):ceil(x2)
be2(u1)=abs(atand(xi(u)/10000));
Ri2(u1)=5.8e-8be2(u1)^5-5.9757e-6be2(u1)^4+1.867e-4be2(u1)^3-0.0013be2(u1)^2-0.0272be2(u1)+0.6715;
di2(u1)=(2sind(90-1.03)/sind(45+1.03))(xi(u)-(xi(u)10000-10000^2tand(1.03))/(10000+xi(u)tand(1.03))+dd/2);
Pi2(u1)=(2sind(90-1.03)/sind(45+1.03))(xi(u)-(xi(u)10000-10000^2tand(1.03))/(10000+xi(u)tand(1.03))+l1/n);
S3_i2(u1)=di2(u1)Pi2(u1);
if di2(u1)>100&&Pi2(u1)>100
S4_i2(u1)=pi(100-6)^2/4;
elseif di2(u1)>100&&Pi2(u1)<100
S4_i2(u1)=(pi100^2*(90-acosd((Pi2(u1)/100))))/360+Pi2(u1)abs(sqrt((100/2)^2-(Pi2(u1)/2)^2))-pi6^2/4;
elseif di2(u1)<100&&Pi2(u1)>100
S4_i2(u1)=(pi100^2(90-acosd((di2(u1)/100))))/360+di2(u1)abs(sqrt((100/2)^2-(di2(u1)/2)^2))-pi6^2/4;
elseif di2(u1)<100&&Pi2(u1)<100
S4_i2(u1)=Pi2(u1)di2(u1)-pi6^2/4;
end
ph1i2(u1)=S4_i2(u1)/S3_i2(u1);
SS3(u1)=(360l1gtl0Ri2(u1)ph1i2(u1))/(pina0*abs(sqrt((xi(u))^2+10000^2)));
u1=u1+1;
end
SS_3=sum(SS3);
SS=SS_3;解释这段代码的意思
Solution
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Geometry
Numerical Methods
Formulas
Angle calculation: atand function
Polynomial function: Ri2 calculation
Trigonometric functions: sind, cosd, acosd
Area calculation: S3_i2, S4_i2 formulas
Theorems
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Suitable Grade Level
Advanced Mathematics