If a simple circuit has 480 volts applied with a current flow of 12 amps, what is its resistance?




To find the resistance of the circuit, you can use Ohm's Law, which is stated as:

\[
V = I \times R
\]

Where:
- \( V \) is the voltage (480 volts),
- \( I \) is the current (12 amps),
- \( R \) is the resistance.

Rearranging the formula to solve for \( R \):

\[
R = \frac{V}{I}
\]

Now, substituting the given values:

\[
R = \frac{480}{12} = 40 \, \text{ohms}
\]

Thus, the resistance is \( 40 \, \text{ohms} \).

Would you like more details or have any questions about this calculation?

Here are 5 related questions:
1. What is the power dissipated in this circuit?
2. How does resistance change if the voltage is increased while keeping current constant?
3. What happens to the current if the resistance is doubled but the voltage remains the same?
4. Can the resistance be negative in any type of circuit?
5. How would the resistance change in a series circuit compared to a parallel one?

**Tip:** Always check your units to ensure you're using compatible values (volts, amps, ohms, etc.) in calculations involving electrical circuits.

If a simple circuit has 480 volts applied with a current flow of 12 amps, what is its resistance?

Learn how to calculate the resistance in a simple electrical circuit with 480 volts and 12 amps using Ohm's Law. This detailed step-by-step solution explains the key concepts and formulas involved. Suitable for students in Grades 9-12.

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