Jada has 45$ to spend at the carnival. Admission is 5$. All rides cost 3$. Which inequality can be used to figure out the greatest number or rides Jada can go on

To determine the greatest number of rides Jada can go on, we need to account for the admission cost and the cost per ride. 

Let's define:
- $ r $ as the number of rides Jada can go on.
- $ 45 $ as the total amount of money Jada has.
- $ 5 $ as the cost of admission.
- $ 3 $ as the cost per ride.

The total cost Jada will spend is the sum of the admission fee and the cost of all the rides:

\[
5 + 3r
\]

Since Jada cannot spend more than $45, we set up the inequality:

\[
5 + 3r \leq 45
\]

Now, solve the inequality to find the maximum number of rides $ r $:

\[
3r \leq 45 - 5
\]
\[
3r \leq 40
\]
\[
r \leq \frac{40}{3}
\]
\[
r \leq 13.33
\]

Since $ r $ represents the number of rides, and it must be a whole number, the greatest number of rides Jada can go on is $ r = 13 $.

So, the inequality that can be used to figure out the greatest number of rides Jada can go on is:

\[
5 + 3r \leq 45
\]

Would you like further details or have any questions?

Here are some related questions:
1. What happens if the cost of a ride increases to $4?
2. If Jada spends $10 on food, how many rides can she afford?
3. What if the admission was $10 instead of $5?
4. How would the inequality change if Jada had $60 instead of $45?
5. How many rides could Jada go on if she wanted to save $5 for souvenirs?

**Tip:** When solving inequalities, always remember to flip the inequality sign if you multiply or divide by a negative number!

Discover how to maximize the number of rides Jada can go on at the carnival using the inequality 5 + 3r ≤ 45. Learn step-by-step with detailed explanations on calculating costs and determining the maximum number of rides. Suitable for Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation