Julia is the oldest of three siblings whose ages are consecutive integers. If the sum of their ages is 4242, find Julia's age.

Let the three siblings' ages be \( x \), \( x+1 \), and \( x+2 \), where \( x+2 \) represents Julia's age as she is the oldest.

The sum of their ages is given as 4242. Therefore, we can write the equation:

\[
x + (x+1) + (x+2) = 4242
\]

Simplifying this equation:

\[
3x + 3 = 4242
\]

Next, subtract 3 from both sides:

\[
3x = 4239
\]

Finally, divide both sides by 3 to solve for \( x \):

\[
x = 1413
\]

Since Julia is the oldest, her age is:

\[
x + 2 = 1413 + 2 = 1415
\]

So, Julia's age is **1415**.

Would you like more details or have any questions?

Here are five related questions for further practice:
1. What would be the age of the youngest sibling?
2. If the sum of their ages was 4260, what would Julia's age be?
3. How would the problem change if there were four siblings with consecutive ages?
4. What if the ages were consecutive even integers?
5. How would you set up an equation if you only knew the sum of the ages and that they were consecutive odd integers?

**Tip:** When working with consecutive integers, the general form for three consecutive integers is \( x \), \( x+1 \), and \( x+2 \), which can help simplify problems like this.

Discover Julia's age in a problem involving three consecutive integer siblings whose ages sum up to 4242. Follow a step-by-step solution method to find out Julia's age. Suitable for Grades 7-9.

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