The function \( f(r) = 2^r + 3^r \) is indeed exponential.

### Explanation:
- **Exponential functions** are generally of the form \( a^r \), where \( a \) is a constant and \( r \) is the variable. Here, \( 2^r \) and \( 3^r \) are both exponential functions, as the variable \( r \) is in the exponent.
- When you add two exponential functions, the result is still an exponential function. Specifically, \( f(r) = 2^r + 3^r \) is the sum of two exponential functions with different bases (2 and 3), making the entire function exponential.

However, it's worth noting that the behavior of this function may differ slightly from a simple exponential function like \( a^r \), but it still has the characteristic of exponential growth.

Would you like more details or have any further questions?

### Relative Questions:
1. What is the growth rate of \( f(r) = 2^r + 3^r \) compared to other exponential functions?
2. How does the function \( f(r) = 2^r + 3^r \) behave as \( r \) approaches infinity?
3. Can the function \( 2^r + 3^r \) be represented as a single exponential function?
4. How does adding a constant \( c \) to \( f(r) = 2^r + 3^r \) affect its classification as an exponential function?
5. How would you differentiate the function \( f(r) = 2^r + 3^r \)?

### Tip:
When dealing with sums of exponential functions, focus on how each term contributes to the overall growth rate, especially as the variable \( r \) increases.

Explore whether the function f(r) = 2^r + 3^r is exponential. This problem involves the concept of exponential functions and summation, demonstrating how two exponential terms combine to form a single exponential function. Suitable for high school students in Grades 9-12.

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