𝑔(𝑝) = 4 𝑝 ; 𝑔𝑖𝑣𝑒𝑛 𝑡ℎ𝑎𝑡 𝑝 = 3 2

Given the function \( g(p) = 4p \), and knowing that \( p = \frac{3}{2} \), you can find \( g(p) \) by substituting \( p \) with \( \frac{3}{2} \) in the function.

\[
g\left(\frac{3}{2}\right) = 4 \times \frac{3}{2}
\]

Now, multiply:

\[
g\left(\frac{3}{2}\right) = \frac{4 \times 3}{2} = \frac{12}{2} = 6
\]

So, the value of \( g(p) \) when \( p = \frac{3}{2} \) is \( \boxed{6} \).

Would you like more details or have any questions about this solution?

Here are some related questions for further exploration:

1. What would \( g(p) \) be if \( p = -\frac{3}{2} \)?
2. How would you find the inverse of the function \( g(p) = 4p \)?
3. What happens to the function \( g(p) \) if you add a constant, say \( g(p) = 4p + 2 \)?
4. How does the graph of \( g(p) = 4p \) look?
5. What is the derivative of \( g(p) = 4p \) with respect to \( p \)?
6. How would \( g(p) \) change if you multiplied \( p \) by 2 instead of 4?
7. What is the value of \( g\left(\frac{5}{2}\right) \)?
8. How would you express \( g(p) \) as a composition of two functions?

**Tip:** When dealing with simple linear functions, substitution and direct multiplication are the quickest methods to evaluate the function for a given input.

Learn how to evaluate the linear function g(p) = 4p when p = 3/2. This problem involves basic algebraic operations and function evaluation. Suitable for students in Grades 7-9.

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