To solve the equation \( p + \frac{6}{4} = 3 \), follow these steps:

1. Simplify the fraction \(\frac{6}{4}\) to \(\frac{3}{2}\):
   \[
   p + \frac{3}{2} = 3
   \]

2. Subtract \(\frac{3}{2}\) from both sides to isolate \(p\):
   \[
   p = 3 - \frac{3}{2}
   \]

3. Convert 3 to a fraction with the same denominator as \(\frac{3}{2}\), which is \(\frac{6}{2}\):
   \[
   p = \frac{6}{2} - \frac{3}{2}
   \]

4. Subtract the fractions:
   \[
   p = \frac{6 - 3}{2} = \frac{3}{2}
   \]

So, the solution is:
\[
p = \frac{3}{2} \quad \text{or} \quad p = 1.5
\]

Would you like more details, or do you have any questions?

Here are 5 related questions to practice:

1. Solve the equation \( p + \frac{7}{5} = 4 \).
2. What is the solution to \( p - \frac{2}{3} = 2 \)?
3. Solve \( p + \frac{5}{3} = \frac{7}{2} \).
4. If \( p + \frac{4}{3} = 5 \), what is \( p \)?
5. What is the solution for \( p + \frac{3}{8} = \frac{7}{4} \)?

**Tip:** Always simplify fractions first to make the equations easier to solve.

Learn how to solve the linear equation p + 6/4 = 3 step-by-step. This solution involves simplifying fractions and isolating the variable to find p = 1.5 or p = 3/2. Ideal for students in Grades 6-8 who are learning about linear equations and fractions.

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