$$ \sqrt{} $$Evaluate equation k(x) =$$ \sqrt2 $$x+5 find k(4) $$ x $$$$ x $$$$  $$

To evaluate the function $ k(x) = \sqrt{2}x + 5 $ at $ x = 4 $, we simply substitute $ x $ with 4 and solve the expression.

Given:
\[ k(x) = \sqrt{2}x + 5 \]

We need to find $ k(4) $:
\[ k(4) = \sqrt{2} \cdot 4 + 5 \]

Now, calculate the value:
\[ k(4) = 4\sqrt{2} + 5 \]

So, the evaluated function at $ x = 4 $ is:
\[ k(4) = 4\sqrt{2} + 5 \]

Would you like more details or have any questions about this process?

Here are 8 relative questions expanding on this information:

1. What is the value of $ \sqrt{2} $ to the nearest hundredth?
2. How would you simplify $ k(x) $ if it was $ k(x) = \sqrt{2}x + c $ for some constant $ c $?
3. How can we graph the function $ k(x) = \sqrt{2}x + 5 $?
4. What is the domain and range of the function $ k(x) = \sqrt{2}x + 5 $?
5. How do you solve for $ x $ when $ k(x) = y $ given $ y $?
6. How does the function $ k(x) $ change if $ \sqrt{2} $ is replaced by another constant?
7. What are the properties of the function $ k(x) = \sqrt{2}x + 5 $?
8. How do you derive the inverse function of $ k(x) = \sqrt{2}x + 5 $?

**Tip:** When substituting values into functions, ensure you accurately follow order of operations to avoid mistakes.

Learn how to evaluate the function k(x) = sqrt(2)x + 5 at x = 4 with a step-by-step solution. This problem involves using the square root function and linear functions to compute the value of the function at a specific point. Suitable for students in Grades 9-12.

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