John and Susan leave a neighborhood restaurant after having dinner. They each walk to their respective homes. John’s home is 3125 feet due north of the restaurant and Susan’s home is 2023 feet due south of the restaurant. John leaves at 7:25pm, traveling at a constant speed of 330 feet per minute, and Susan leaves at 7:30 pm, traveling at a constant speed of 215 feet per minute. 

We can analyze this problem by calculating the time it will take John and Susan to reach their homes and then comparing their progress relative to the restaurant.

### John's journey:
- **Distance to home**: 3125 feet
- **Speed**: 330 feet per minute
- **Departure time**: 7:25 PM

John’s time to reach his home:
\[
\text{Time for John} = \frac{\text{Distance}}{\text{Speed}} = \frac{3125}{330} \approx 9.47 \, \text{minutes}
\]
Thus, John will arrive home at approximately 7:34:28 PM (7:25 PM + 9.47 minutes).

### Susan's journey:
- **Distance to home**: 2023 feet
- **Speed**: 215 feet per minute
- **Departure time**: 7:30 PM

Susan’s time to reach her home:
\[
\text{Time for Susan} = \frac{\text{Distance}}{\text{Speed}} = \frac{2023}{215} \approx 9.41 \, \text{minutes}
\]
Thus, Susan will arrive home at approximately 7:39:25 PM (7:30 PM + 9.41 minutes).

### Relative question:
Now we can ask some additional questions based on this scenario:

1. **When is John at the same distance from the restaurant as Susan?**
2. **How far apart are John and Susan at 7:30 PM?**
3. **Who gets home first, and by how many seconds?**
4. **What is the total distance between John and Susan’s homes?**
5. **If Susan walked faster at 250 feet per minute, when would she arrive home?**

#### Tip:
To solve problems with different travel times and speeds, always start by calculating the time each person takes to cover the distance.

John and Susan leave a neighborhood restaurant after having dinner. They each walk to their respective homes. John’s home is 3125 feet due north of the restaurant and Susan’s home is 2023 feet due south of the restaurant. John leaves at 7:25pm, traveling at a constant speed of 330 feet per minute, and Susan leaves at 7:30 pm, traveling at a constant speed of 215 feet per minute.

Solve a problem involving John and Susan walking home from a restaurant, calculating their travel times based on distance and speed. Learn how to determine who reaches home first and compare their relative distances over time. Suitable for Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation