https://file.aiquickdraw.com/mathbot/file/1725896251065xgkb450z.jpg

To solve this problem, we need to find the percentage of benzene in the new mixture.

### Given:
- The first liquid contains 25% benzene.
- The second liquid contains 30% benzene.
- The mixture is made by mixing 6 parts of the first liquid with 4 parts of the second liquid.

### Step-by-Step Solution:
1. **Determine the amount of benzene in each liquid:**
   - Benzene in the first liquid = \( 25\% \) of 6 parts = \( 0.25 \times 6 = 1.5 \) parts.
   - Benzene in the second liquid = \( 30\% \) of 4 parts = \( 0.30 \times 4 = 1.2 \) parts.

2. **Total benzene in the mixture:**
   - Total benzene = \( 1.5 \) parts (from the first liquid) + \( 1.2 \) parts (from the second liquid) = \( 2.7 \) parts.

3. **Total amount of liquid in the mixture:**
   - Total liquid = 6 parts (first liquid) + 4 parts (second liquid) = 10 parts.

4. **Calculate the percentage of benzene in the mixture:**
   \[
   \text{Percentage of benzene} = \left(\frac{\text{Total benzene}}{\text{Total liquid}}\right) \times 100 = \left(\frac{2.7}{10}\right) \times 100 = 27\%
   \]

### Answer:
The percentage of benzene in the new mixture is **27%**.

Would you like any further details or have any questions? Here are some related questions to explore:

1. How would the percentage change if the first liquid contained 20% benzene instead of 25%?
2. What if the ratio of the two liquids was reversed (4 parts of the first and 6 parts of the second)?
3. How can this problem be generalized to any percentage of benzene in the two liquids?
4. How would you solve this problem if three liquids were mixed instead of two?
5. What is the significance of the weighted average in solving mixture problems?

**Tip:** Always check if the ratios given in the problem are by volume, mass, or any other measure to apply the correct method.

One type of liquid contains 25% of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

Find out how to calculate the percentage of benzene in a mixture of two liquids containing 25% and 30% benzene, mixed in a ratio of 6:4. This solution includes detailed steps involving percentage calculation and the weighted average theorem.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation