if 10  liters of a 20% solution is mixed with5 liters of a 50% solution what is the potency of the final mixture?

To find the potency of the final mixture, we use the concept of weighted averages based on the amounts and concentrations of the two solutions.

### Step-by-step solution:
1. **Amount of pure substance in each solution:**
   - For the 20% solution (10 liters):  
     Pure substance = \( 20\% \times 10 = 0.2 \times 10 = 2 \) liters.
   - For the 50% solution (5 liters):  
     Pure substance = \( 50\% \times 5 = 0.5 \times 5 = 2.5 \) liters.

2. **Total amount of pure substance in the final mixture:**
   Total pure substance = \( 2 + 2.5 = 4.5 \) liters.

3. **Total volume of the final mixture:**
   Total volume = \( 10 + 5 = 15 \) liters.

4. **Potency (concentration) of the final mixture:**
   \[
   \text{Potency} = \frac{\text{Total pure substance}}{\text{Total volume}} \times 100
   \]
   \[
   \text{Potency} = \frac{4.5}{15} \times 100 = 30\%
   \]

Thus, the potency of the final mixture is **30%**.

Would you like more details or have any questions? Here are 5 related questions:

1. How do you find the volume of pure substance in a solution?
2. What happens to the concentration when two solutions are mixed?
3. Can the concentration ever be higher than the original highest solution?
4. How does the volume affect the final potency?
5. What is the difference between weight percent and volume percent?

**Tip:** Always check the total volume and the concentration carefully to ensure you account for all components in a mixture problem.

if 10 liters of a 20% solution is mixed with 5 liters of a 50% solution what is the potency of the final mixture?

Discover how to calculate the potency of a mixture when 10 liters of a 20% solution is mixed with 5 liters of a 50% solution. Learn key concepts like weighted averages and percentage calculations, suitable for students in Grades 8-10.

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