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To find the area of a rhombus, we can use the formula involving the lengths of its diagonals:

\[
\text{Area} = \frac{1}{2} \times d_1 \times d_2
\]

Where \( d_1 \) and \( d_2 \) are the lengths of the diagonals of the rhombus. In the image:

- One diagonal is \( 6 + 6 = 12 \, \text{ft} \) (horizontal diagonal).
- The other diagonal is \( 8 + 8 = 16 \, \text{ft} \) (vertical diagonal).

Now, applying the formula:

\[
\text{Area} = \frac{1}{2} \times 12 \, \text{ft} \times 16 \, \text{ft}
\]

Let's calculate that.The area of the rhombus is \( 96 \, \text{ft}^2 \).

Do you want more details or have any questions? Here are five related questions to deepen your understanding:

1. What is the relationship between the diagonals of a rhombus?
2. How do you find the perimeter of a rhombus if you know the side length?
3. Can the diagonals of a rhombus ever be equal?
4. How does the area of a rhombus compare to the area of a square?
5. How would the formula change if the shape were a kite instead of a rhombus?

**Tip:** The diagonals of a rhombus not only bisect each other but also meet at right angles, creating four right triangles within the rhombus.

Find the area of the rhombus with diagonals measuring 12 ft and 16 ft.

Learn how to calculate the area of a rhombus using its diagonals. This example involves diagonals measuring 12 ft and 16 ft. By applying the formula (1/2) * d1 * d2, the area of the rhombus is found to be 96 ft². Suitable for students in Grades 7-9.

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