https://file.aiquickdraw.com/mathbot/file/17265070502099e6iir9g.jpg

To find the area of the rhombus, we can use the formula:

\[
\text{Area of a rhombus} = \frac{1}{2} \times d_1 \times d_2
\]

where \(d_1\) and \(d_2\) are the lengths of the diagonals.

From the image, we can see that the diagonals are formed by two pairs of congruent right triangles. One diagonal is the sum of the two 10-foot segments, so:

\[
d_1 = 10 + 10 = 20 \, \text{ft}
\]

The other diagonal is the sum of the two 5-foot segments, so:

\[
d_2 = 5 + 5 = 10 \, \text{ft}
\]

Now, applying the formula:

\[
\text{Area} = \frac{1}{2} \times 20 \times 10 = \frac{1}{2} \times 200 = 100 \, \text{ft}^2
\]

Thus, the area of the rhombus is **100 square feet**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the area change if one diagonal were doubled?
2. What is the perimeter of this rhombus?
3. Can the area of a rhombus be found using trigonometry?
4. What other shapes share the same area formula as a rhombus?
5. How do the properties of diagonals in a rhombus help with calculating its area?

**Tip:** The diagonals of a rhombus always bisect each other at right angles, which is a key property for finding the area.

Learn how to calculate the area of a rhombus when given the lengths of its diagonals. This guide provides a step-by-step solution using the formula Area = 0.5 * d1 * d2, with diagonals of 20 feet and 10 feet. Explore key geometric concepts and properties of rhombuses, suitable for students in Grades 6-8.

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