Math Problem Statement

Area of rhombus is 480cm² and one of its diagonal is 48cm find: 1.the length of other diagonal. 2.each side. 3.perimeter 4.the distance between it's side

Solution

Given that the area of a rhombus is 480 cm² and one of its diagonals is 48 cm, we need to find the following:

1. Length of the Other Diagonal

The area AA of a rhombus can be calculated using the formula: A=12×d1×d2A = \frac{1}{2} \times d_1 \times d_2 where d1d_1 and d2d_2 are the lengths of the diagonals.

We know: 480=12×48×d2480 = \frac{1}{2} \times 48 \times d_2

To find d2d_2: d2=2×48048=96048=20 cmd_2 = \frac{2 \times 480}{48} = \frac{960}{48} = 20 \text{ cm}

2. Length of Each Side

The length of a side ss of the rhombus can be calculated using the relationship between the diagonals and the sides: s=(d12)2+(d22)2s = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2} Substituting the values d1=48d_1 = 48 cm and d2=20d_2 = 20 cm: s=(482)2+(202)2=242+102=576+100=676=26 cms = \sqrt{\left(\frac{48}{2}\right)^2 + \left(\frac{20}{2}\right)^2} = \sqrt{24^2 + 10^2} = \sqrt{576 + 100} = \sqrt{676} = 26 \text{ cm}

3. Perimeter of the Rhombus

The perimeter PP of a rhombus is given by: P=4×sP = 4 \times s So, substituting the value of s=26s = 26 cm: P=4×26=104 cmP = 4 \times 26 = 104 \text{ cm}

4. Distance Between Its Sides

The distance between the sides (also known as the height hh) can be found using the area formula for the rhombus: A=s×hA = s \times h Rearranging to find hh: h=As=4802618.46 cmh = \frac{A}{s} = \frac{480}{26} \approx 18.46 \text{ cm}

Summary of Results

  1. Length of the other diagonal d2=20d_2 = 20 cm.
  2. Length of each side s=26s = 26 cm.
  3. Perimeter of the rhombus P=104P = 104 cm.
  4. Distance between the sides (height) h18.46h \approx 18.46 cm.

Would you like any more details, or do you have any questions?


Here are 5 related questions to further your understanding:

  1. How would the area change if the other diagonal was doubled?
  2. What is the relationship between the diagonals and the area of a rhombus?
  3. How does the perimeter of a rhombus compare to its diagonals?
  4. What are the properties of a rhombus that distinguish it from other quadrilaterals?
  5. How would you find the area if both diagonals were unknown?

Tip: Remember that the diagonals of a rhombus bisect each other at right angles, forming four right-angled triangles within the rhombus.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of Rhombus
Diagonals of Rhombus
Perimeter of Rhombus

Formulas

Area of Rhombus = 0.5 * d1 * d2
Perimeter of Rhombus = 4 * side length

Theorems

Properties of Rhombus

Suitable Grade Level

Grades 7-9