Math Problem Statement

(a, b) ∈ ℝ², c > 0 |a| < c et |b| < c → |(a + b) / 2| + |(a - b) / 2| < c

Solution

The image contains an inequality and some given conditions. Let's break it down:

Conditions:

  1. a,bR2a, b \in \mathbb{R}^2 (This seems to imply that aa and bb are real numbers, possibly in a two-dimensional real space, though this is likely shorthand for a,bRa, b \in \mathbb{R}).
  2. c>0c > 0

Given Inequalities:

  1. a<c|a| < c and b<c|b| < c

    This means that the absolute values of both aa and bb are less than cc, where cc is positive.

  2. Conclusion:

    The inequality then transitions to: a+b2+ab2<c\left| \frac{a + b}{2} \right| + \left| \frac{a - b}{2} \right| < c This can be interpreted as a condition that combines the averages of the sums and differences of aa and bb, and shows that their magnitudes are bounded by cc.

Interpretation:

This is a form of triangle inequality. It essentially states that if the magnitudes (absolute values) of two numbers are less than some positive constant cc, then certain combinations of their sums and differences are also bounded by the same cc.

Do you want a more detailed explanation or proof of how this inequality is derived? Here are some related questions:

  1. What is the triangle inequality, and how does it relate to this form?
  2. How does this inequality change if aa or bb were negative?
  3. How can this inequality be applied to geometric interpretations in real space?
  4. Can we extend this result to higher dimensions (e.g., 3D space)?
  5. What happens if cc is allowed to approach zero?

Tip: The absolute value function helps simplify and ensure non-negative results when working with real numbers, which is useful when bounding sums or differences.

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Math Problem Analysis

Mathematical Concepts

Algebra
Inequalities
Absolute Value
Triangle Inequality

Formulas

|a| < c
|b| < c
|(a + b) / 2| + |(a - b) / 2| < c

Theorems

Triangle Inequality

Suitable Grade Level

University level (Advanced Algebra or Analysis)