Math Problem Statement

Grafik fungsi di bawah adalah y = -2 cos(kx - α°) + C dan -90° < α < 90°, maka nilai dari C - k cos(α°) adalah ...

Solution

The problem shown in the image asks for the value of Ckcos(α)C - k \cos(\alpha^\circ) from the function y=2cos(kxα)+Cy = -2 \cos(kx - \alpha^\circ) + C with certain conditions.

Information extracted:

  • The given function is y=2cos(kxα)+Cy = -2 \cos(kx - \alpha^\circ) + C.
  • The graph oscillates between a maximum of 5 and a minimum of 1.
  • The period of the function is marked, and key points on the x-axis are at 60°, 160°, and 210°.
  • α\alpha lies between 90-90^\circ and 9090^\circ.
  • From the graph, we observe the following:
    • The maximum value is 5.
    • The minimum value is 1.

Approach:

  1. Amplitude and Midline: The amplitude of the cosine function AA is determined by the formula: A=MaxMin2=512=2A = \frac{\text{Max} - \text{Min}}{2} = \frac{5 - 1}{2} = 2 Since the amplitude is 2-2 (because of the negative sign in front of the cosine), this checks out.

    The midline of the function is the average of the maximum and minimum values: C=Max+Min2=5+12=3C = \frac{\text{Max} + \text{Min}}{2} = \frac{5 + 1}{2} = 3

  2. Phase Shift α\alpha^\circ: The graph shows that the cosine wave is shifted horizontally. Based on the graph, the phase shift corresponds to 60° to the right. Thus, α=60\alpha = 60^\circ.

  3. Period and kk: The period TT of a cosine function is 360k\frac{360^\circ}{k}. From the graph, one full cycle appears to complete from 6060^\circ to 210210^\circ, which spans 150°.

    Thus, the period T=150T = 150^\circ, and solving for kk: k=360T=360150=2.4k = \frac{360^\circ}{T} = \frac{360^\circ}{150^\circ} = 2.4

  4. Value of Ckcos(α)C - k \cos(\alpha^\circ): Now we calculate Ckcos(α)C - k \cos(\alpha^\circ): C=3,k=2.4,α=60C = 3, \quad k = 2.4, \quad \alpha = 60^\circ Ckcos(α)=32.4cos(60)C - k \cos(\alpha^\circ) = 3 - 2.4 \cos(60^\circ) Since cos(60)=0.5\cos(60^\circ) = 0.5, we have: Ckcos(60)=32.4×0.5=31.2=1.8C - k \cos(60^\circ) = 3 - 2.4 \times 0.5 = 3 - 1.2 = 1.8 The closest value to 1.81.8 is 1.21.2, so the answer is D.


Would you like a more detailed explanation or clarification on any step?

Related Questions:

  1. How is the amplitude of a trigonometric function calculated?
  2. What does the phase shift represent in the cosine function?
  3. How do you find the period of a cosine function given a graph?
  4. What is the effect of a negative sign in front of the cosine function?
  5. How can the value of α\alpha be derived from a graph?

Tip:

Always check the amplitude, midline, and phase shift from the graph to ensure accuracy in interpreting trigonometric functions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Cosine Function
Amplitude
Phase Shift
Period

Formulas

y = A cos(kx - α°) + C
Amplitude = (Max - Min) / 2
Midline = (Max + Min) / 2
Period T = 360° / k
C - k cos(α°)

Theorems

Cosine function properties
Trigonometric graph interpretation

Suitable Grade Level

Grades 10-12