Math Problem Statement
Solution
The problem shown in the image asks for the value of from the function with certain conditions.
Information extracted:
- The given function is .
- The graph oscillates between a maximum of 5 and a minimum of 1.
- The period of the function is marked, and key points on the x-axis are at 60°, 160°, and 210°.
- lies between and .
- From the graph, we observe the following:
- The maximum value is 5.
- The minimum value is 1.
Approach:
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Amplitude and Midline: The amplitude of the cosine function is determined by the formula: Since the amplitude is (because of the negative sign in front of the cosine), this checks out.
The midline of the function is the average of the maximum and minimum values:
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Phase Shift : The graph shows that the cosine wave is shifted horizontally. Based on the graph, the phase shift corresponds to 60° to the right. Thus, .
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Period and : The period of a cosine function is . From the graph, one full cycle appears to complete from to , which spans 150°.
Thus, the period , and solving for :
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Value of : Now we calculate : Since , we have: The closest value to is , so the answer is D.
Would you like a more detailed explanation or clarification on any step?
Related Questions:
- How is the amplitude of a trigonometric function calculated?
- What does the phase shift represent in the cosine function?
- How do you find the period of a cosine function given a graph?
- What is the effect of a negative sign in front of the cosine function?
- How can the value of be derived from a graph?
Tip:
Always check the amplitude, midline, and phase shift from the graph to ensure accuracy in interpreting trigonometric functions.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Cosine Function
Amplitude
Phase Shift
Period
Formulas
y = A cos(kx - α°) + C
Amplitude = (Max - Min) / 2
Midline = (Max + Min) / 2
Period T = 360° / k
C - k cos(α°)
Theorems
Cosine function properties
Trigonometric graph interpretation
Suitable Grade Level
Grades 10-12
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