Let's solve the expression step by step.

Given the formula:

\[
I = \frac{V}{R}
\]

Substitute the given values: \( V = 30 \, \text{mV} \) (millivolts) and \( R = 1.8 \times 10^3 \, \Omega \) (ohms):

\[
I = \frac{30 \, \text{mV}}{1.8 \times 10^3 \, \Omega}
\]

Since \( 1 \, \text{mV} = 10^{-3} \, \text{V} \), convert the voltage to volts:

\[
V = 30 \, \text{mV} = 30 \times 10^{-3} \, \text{V} = 0.03 \, \text{V}
\]

Now, calculate the current \( I \):

\[
I = \frac{0.03 \, \text{V}}{1.8 \times 10^3 \, \Omega}
\]

First, simplify the denominator:

\[
1.8 \times 10^3 = 1,800 \, \Omega
\]

Now, divide the numerator by the denominator:

\[
I = \frac{0.03 \, \text{V}}{1,800 \, \Omega}
\]

Simplify the division:

\[
I = 0.00001667 \, \text{A}
\]

This can be expressed in microamperes (\( \mu A \)):

\[
I = 16.67 \, \mu A
\]

So, the current \( I \) is approximately \( 16.67 \, \mu A \) (microamperes).

Would you like more details on this calculation or have any questions?

Here are 5 related questions to consider:

1. What would the current be if the resistance were doubled?
2. How does the current change if the voltage is reduced to half?
3. What is the power dissipated across the resistor with the given current and resistance?
4. How would you express the resistance in kilohms (kΩ)?
5. How would the current change if the voltage were in volts instead of millivolts?

**Tip:** When dealing with small voltages like millivolts, it's helpful to convert them into volts for easier calculations.

Learn how to solve an Ohm's Law problem involving a voltage of 30 millivolts and resistance of 1.8 * 10^3 ohms. Step-by-step solution includes converting millivolts to volts and calculating the current using Ohm's Law formula. Suitable for advanced high school students and beyond.

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