To find the resistance \( R \) using Ohm's Law, you can use the formula:

\[
R = \frac{V}{I}
\]

Given:
- \( V = 160 \text{ mV} = 160 \times 10^{-3} \text{ V} \)
- \( I = 800 \text{ μA} = 800 \times 10^{-6} \text{ A} \)

Substitute the values into the formula:

\[
R = \frac{160 \times 10^{-3} \text{ V}}{800 \times 10^{-6} \text{ A}}
\]

Now calculate the resistance:

\[
R = \frac{160 \times 10^{-3}}{800 \times 10^{-6}} = \frac{160 \times 10^{-3}}{0.8 \times 10^{-3}} = \frac{160}{0.8} = 200 \, \text{ohms}
\]

So, the resistance \( R \) is \( 200 \, \Omega \).

Would you like more details or have any other questions?

Here are some related questions:
1. How does Ohm's Law relate voltage, current, and resistance?
2. What are the effects of increasing resistance on current for a constant voltage?
3. Can you explain the difference between mV and μA units?
4. How can resistance be measured practically?
5. What happens if the resistance in a circuit is zero?

**Tip:** Remember that converting units properly is crucial for solving physics problems accurately.

Learn how to calculate resistance using Ohm's Law with V = 160 mV and I = 800 μA. Follow a step-by-step solution and understand the concepts of voltage, current, and resistance in electric circuits. Suitable for high school students studying physics.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation