Let's solve the expression step by step:

Given expression:
\[ 6 \div [3 \times (3 - 1)] \div [2 \times (2 + 2)] \]

First, solve the parentheses inside the brackets:
\[ 3 - 1 = 2 \]
\[ 2 + 2 = 4 \]

Now substitute back into the expression:
\[ 6 \div [3 \times 2] \div [2 \times 4] \]

Next, solve the expressions inside the brackets:
\[ 3 \times 2 = 6 \]
\[ 2 \times 4 = 8 \]

Now the expression becomes:
\[ 6 \div 6 \div 8 \]

Proceed with the division from left to right:
\[ 6 \div 6 = 1 \]
\[ 1 \div 8 = \frac{1}{8} \]

So, the final answer is:
\[ \frac{1}{8} \]

Would you like more details or have any questions?

Here are 5 questions you might be interested in:
1. How do you handle nested parentheses and brackets in expressions?
2. What are some techniques for simplifying complex fractions?
3. Can you explain the distributive property in algebra?
4. How do you factor polynomials?
5. What is the difference between permutations and combinations?

Tip: When dealing with nested expressions, always solve the innermost parentheses or brackets first, and work your way outward.

Learn how to solve the arithmetic expression 6 divided by the product of expressions inside brackets. This problem involves arithmetic operations including division and multiplication. Suitable for students in Grades 5-6.

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