Let's solve the expression step by step:

Given expression:
\[ 6 \div 3 \times (3 - 1) \div 2 \times (2 + 2) \]

First, solve the parentheses:
\[ 3 - 1 = 2 \]
\[ 2 + 2 = 4 \]

Now substitute back into the expression:
\[ 6 \div 3 \times 2 \div 2 \times 4 \]

Next, follow the order of operations (PEMDAS/BODMAS):

1. Division and multiplication from left to right:
\[ 6 \div 3 = 2 \]
\[ 2 \times 2 = 4 \]
\[ 4 \div 2 = 2 \]
\[ 2 \times 4 = 8 \]

So, the final answer is:
\[ 8 \]

Would you like more details or have any questions?

Here are 5 questions you might be interested in:
1. How do you solve more complex expressions?
2. What is the order of operations?
3. Can you help with solving algebraic equations?
4. How do parentheses affect calculations?
5. What are some common mistakes in solving expressions?

Tip: Always remember to follow the order of operations to ensure you get the correct result.

Learn how to solve the expression 6 divided by 3 times the quantity 3 minus 1, divided by 2 times the quantity 2 plus 2 step by step. This problem covers key mathematical concepts including order of operations, parentheses, division, and multiplication. Suitable for students in Grades 6-8.

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