$$ x^2 - 8x + 15 = (x-3)(x-5) $$ facorize this 

To factorize the equation $x^2 - 8x + 15 = (x-3)(x-5)$:

1. Start with the left side of the equation, $x^2 - 8x + 15$.
2. Find two numbers that multiply to $15$ and add up to $-8$. These numbers are $-3$ and $-5$.
3. Rewrite the quadratic as $(x-3)(x-5)$.

Thus, the factorized form of the equation is:

\[
x^2 - 8x + 15 = (x-3)(x-5)
\]

Would you like more details or have any questions?

Here are some questions you might want to ask:

1. How do I factor different types of quadratic equations?
2. What are common factoring techniques for polynomials?
3. Can you explain how to complete the square?
4. How do I solve quadratic equations using the quadratic formula?
5. What is the importance of factoring in algebra?

**Tip:** Always check your factors by expanding them to ensure they match the original expression.

Learn how to factorize the quadratic equation x^2 - 8x + 15 into its linear factors (x-3)(x-5). This problem covers algebraic factoring techniques suitable for students in Grades 7-9.

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