Solve:    2x + 3  < -22 + 3x

Group of answer choices

X < 4

X < 5

x > 5

x > 4

To solve the inequality \(2x + 3 < -22 + 3x\), let's follow these steps:

1. **Move all terms involving \(x\) to one side and constant terms to the other side:**

\[
2x + 3 < -22 + 3x
\]

Subtract \(2x\) from both sides:

\[
3 < -22 + x
\]

2. **Isolate \(x\) by adding 22 to both sides:**

\[
3 + 22 < x
\]

\[
25 < x
\]

3. **Rewrite the inequality:**

\[
x > 25
\]

There is no option for \(x > 25\) among the given choices. Assuming there might be an error in the problem or choices, the closest option to the correct answer \(x > 25\) would technically be **"x > 5"** but note that \(x > 25\) does not match any of the options provided. If this is a typo, please verify the inequality.

Would you like more details, or do you have any questions?

Here are 5 related questions that expand on this topic:

1. How do you solve inequalities involving fractions?
2. What happens if you multiply or divide an inequality by a negative number?
3. How do you graph solutions to inequalities on a number line?
4. What is the difference between solving linear inequalities and quadratic inequalities?
5. How do you solve a compound inequality?

**Tip:** When solving inequalities, always perform the same operation on both sides to maintain the inequality's direction, except when multiplying or dividing by a negative number.

Learn how to solve the inequality 2x + 3 < -22 + 3x with a detailed step-by-step solution. This problem involves manipulating inequalities and solving linear equations, suitable for students in Grades 7-9.

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