Solve:    2x + 3  < -22 + 3x
 
Group of answer choices

X < 4

X < 5

x > 5

x > 4

Let's solve the inequality \(2x + 3 < -22 + 3x\).

### Step 1: Subtract \(2x\) from both sides.
\[
2x + 3 - 2x < -22 + 3x - 2x
\]
\[
3 < -22 + x
\]

### Step 2: Add 22 to both sides.
\[
3 + 22 < x
\]
\[
25 < x
\]

This inequality can also be written as:
\[
x > 25
\]

However, this doesn't match any of the given options exactly. It seems that there's a mismatch in the problem setup or the answer choices provided.

Please double-check the problem statement or answer choices, but based on this solution, the correct form should be \( x > 25 \).

Would you like more details or do you have any questions? 

Here are some related questions:
1. How do you solve inequalities involving fractions?
2. What happens when you multiply or divide an inequality by a negative number?
3. Can you graph the solution of the inequality \(2x + 3 < -22 + 3x\)?
4. How does the solution change if the inequality sign is reversed?
5. What are the steps to solving a compound inequality?

**Tip:** Always double-check the inequality by substituting values to verify if the solution is correct.

Learn how to solve the inequality 2x + 3 < -22 + 3x with a detailed step-by-step solution. This problem involves inequalities in algebra, covering basic inequality solving techniques. Suitable for students in Grades 7-9.

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