Let's solve the equation step by step:

Given equation:
\[
3(y + 2) + 2(y - 3) = 15
\]

### Step 1: Distribute the constants inside the parentheses.
\[
3y + 6 + 2y - 6 = 15
\]

### Step 2: Combine like terms on the left side.
\[
(3y + 2y) + (6 - 6) = 15
\]
\[
5y + 0 = 15
\]
\[
5y = 15
\]

### Step 3: Solve for \( y \).
\[
y = \frac{15}{5} = 3
\]

### Final Answer:
\[
y = 3
\]

Would you like more details on this solution or have any questions?

Here are some related questions to practice:
1. Solve \( 4(x + 1) + 3(x - 2) = 10 \).
2. Solve \( 2(2z - 3) + 5(1 - z) = 7 \).
3. Solve \( 7(a - 1) - 2(a + 4) = 5 \).
4. Solve \( 3(m + 2) + 2(m - 5) = 9 \).
5. Solve \( 5(n + 4) - 3(n - 2) = 16 \).

**Tip:** Always distribute and combine like terms carefully to avoid mistakes.

Learn how to solve the equation 3(y + 2) + 2(y - 3) = 15 with a detailed step-by-step solution. This problem covers key algebraic concepts, including the distributive property and combining like terms. Suitable for students in Grades 7-9.

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