Math Problem Statement

求解图中的问题

Solution

To solve the given problem, we need to find dydx\frac{dy}{dx} when t=π4t = \frac{\pi}{4}.

Given the parametric equations: x=sintx = \sin t y=tsint+costy = t \sin t + \cos t

We will follow these steps:

  1. Differentiate xx and yy with respect to tt.
  2. Use the chain rule to find dydx\frac{dy}{dx}.

First, let's find dxdt\frac{dx}{dt}: dxdt=cost\frac{dx}{dt} = \cos t

Next, let's find dydt\frac{dy}{dt}: dydt=ddt(tsint+cost)\frac{dy}{dt} = \frac{d}{dt} (t \sin t + \cos t) Using the product rule and chain rule: dydt=sint+tcostsint\frac{dy}{dt} = \sin t + t \cos t - \sin t dydt=tcost\frac{dy}{dt} = t \cos t

Now, using the chain rule: dydx=dydtdxdt=tcostcost=t\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}} = \frac{t \cos t}{\cos t} = t

Finally, we substitute t=π4t = \frac{\pi}{4} into the result: dydxt=π4=π4\frac{dy}{dx} \bigg|_{t = \frac{\pi}{4}} = \frac{\pi}{4}

So, the value of dydx\frac{dy}{dx} when t=π4t = \frac{\pi}{4} is π4\frac{\pi}{4}.

Would you like any further details or have any questions? Here are some related questions you might want to explore:

  1. How do you find the second derivative d2ydx2\frac{d^2y}{dx^2} for parametric equations?
  2. What are some applications of parametric equations in real-world problems?
  3. Can you provide examples of parametric equations in polar coordinates?
  4. How do you convert parametric equations to Cartesian form?
  5. What are some common techniques for solving differential equations?

Tip: When working with parametric equations, always remember to use the chain rule for differentiation to relate the derivatives with respect to different variables.

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Math Problem Analysis

Mathematical Concepts

Parametric Equations
Differentiation
Chain Rule

Formulas

Chain rule for differentiation

Theorems

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Suitable Grade Level

Advanced High School / Undergraduate Level